A 220v 60hz of alternating current is connected to an inductance of 3.5h what is the current passing through the inductor
Solution.
V=220V;V=220V;V=220V;
f=60Hz;f=60Hz;f=60Hz;
L=3.5H;L=3.5H;L=3.5H;
I−?;I-?;I−?;
I=VXL;I=\dfrac{V}{X_L};I=XLV;
XL=2πfL;X_L=2\pi f L;XL=2πfL;
XL=2⋅3.14⋅60⋅3.5=1318.8Ω;X_L=2\sdot3.14\sdot60\sdot3.5=1318.8\Omega;XL=2⋅3.14⋅60⋅3.5=1318.8Ω;
I=2201318.8=0.167A;I=\dfrac{220}{1318.8}=0.167A;I=1318.8220=0.167A;
Answer: I=0.167A.I=0.167A.I=0.167A.
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