Question

Two circuits present the same resistance to the current. In one circuit the battery causing the flow of current has a voltage of 9.0 V, and the current is 3.0 A. In the other circuit the battery has a voltage of 1.5 V. What is the current in this other circuit?

Answer 1

$V=IR$

For the first circuit:

$R= \frac{9}{3}=3\Omega$

For the second circuit

$I=\frac{1.5}{3}=0.5A$