Question

. How much energy is stored in a 150µF capacitor if a 12V battery is connected across

it? How much charge is stored in this capacitor?

Answer 1

Charge

$Q=CV$

$$Q=12\times150\times10^{-6}=18\times10^{-4}C$$

Energy

$U=\frac{1}{2}CV^2$

$$U=\frac{1}{2}\times{150\times10^{-6}\times12^2}=10.8\times10^{-3}J$$