Question

A uniform electric field of 500 N/C is established between two oppositely charged metal plates. A particle with a charge of +0.003 C is moved from the bottom (negatively charged) plate to the top plate. (Imagine that the string is tied to the charged that is pulling it upward). The distance between the plate is 5cm.

A. What is the change in the potential energy of the charge?

B. What is the change in electric potential from the bottom to the top plate?

Answer 1

Solution;

$\Delta U_E=-qEd$

$\Delta U_E=-0.003×500×0.05$

$\Delta U_E=0.075Nm$