Question

The capacitors have values C1= 2.0 uf and C2= 4.0 uF, C3=5.0 uF C4= 7.0 uF and the potential difference across the battery is 9.0 V. Assume that the capacitors are connected in parallel?

Answer 1

Capacitor

$C_1=2\mu F\\C_2=4\mu F\\C_3=5\mu F\\C_4=7\mu F$

$V=9V$

All capacitor connected in parallel combination

$C_{net}=C_1+C_2+C_3+C_4$

Put value

$$C_{net}=(2+4+5+7)\times10^{-6}=18\mu F$$

Charge

$Q=CV$

$$Q=18\times10^{-6}\times9=162\times10^{-6}=162\mu F$$