Question

Two circuits present the same resistance to the current. In one circuit the battery causing the flow of current has a voltage of 9.0 V, and the current is 3.0 A. In the other circuit the battery has a voltage of 1.5 V. What is the current in this other circuit?

Answer 1

Answer

Using ohm law

$I'=\frac{V'I}{V}\\=\frac{1.5*3}{9}\\=0.5A$