Question

In 2.0 s, 1.9*10¹⁹ electrons pass a certain point in a wire. what it the current / in the wire?

Answer 1

We know that

q=ne

$$I=\frac{ne}{t}=\frac{1.9\times10^{19}\times1.6\times10^{-19}}{2}=1.52A$$