Question

How much is the capacitance if the voltage is 40 V and the equivalent charge of the circuit is 2 C?

Answer 1

Q = 2 C

V = 40 V

We know, Q = C V

$Capacitance C = \frac{Q}{V}$

Therefore, $C = \frac{2}{40}$

Hence C = 0.05 F

Final Answer: C = 0.05 F