Question #303686

A 2.5 kΩ resistor dissipates 0.5 W. The energy by this resistor in 3 minutes is _________.


1
Expert's answer
2022-03-01T15:34:24-0500

Power

P=WtP=\frac{W}{t}

E=P×tE=P\times t

E=0.5×3×60=90JE=0.5\times3\times60=90J


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