Question

An electrolytic capacitor is charged to 15 V when a constant current of 1.0 A is passed through it for 30 µs. What is the value of its capacitance?     

Answer 1

$Charge, Q=It=1\times 30\times 10^{-6}=3\times 10^{-5}C$

Capacitance, $C=Q/V=\frac{3\times 10^{-5}}{15}=2.0 \mu F$