Answer to Question #302766 in Electric Circuits for martinez solman

Question

The electrostatic field strength of a proton at distance r is E₁. What would be the strength of the field, E₂ when the distance is doubled?

Answer 1

We know that

Electric field

$E\alpha\frac{1}{r^2}$

We can written as

$\frac{E_1}{E_2}=\frac{r_2^2}{r_1^2}$

$r_2=2r_1$

Put value

$\frac{E_1}{E_2}=(\frac{2r_1}{r_1})^2=4$

$E_2=\frac{E_1}{4}$