Determine the total capacitance if a 30 pF capacitor is connected in series with a 0.03 μF capacitor. Capacitance =
Gives
C1=30pFC2=30pFC_1=30pF \\C_2=30pFC1=30pFC2=30pF
Now C1C_1C1 And C2_22 Is series combination
Cnet=C1C2C1+C2C_{net}=\frac{C_1C_2}{C_1+C_2}Cnet=C1+C2C1C2
Cnet=30×3030+30pF=15pFC{net}=\frac{30\times30}{30+30}pF=15pFCnet=30+3030×30pF=15pF
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