Question #302752

A uniform piece of wire has a diameter of 0.30 mm and length 2.25 m has a resistance of 28 Ω. Find the resistivity of the wire. 


1
Expert's answer
2022-02-25T11:11:57-0500

The resistivity of a conductor is given by

R=ρLAR=\rho \dfrac{L}{A}

Where 

AA is the Area

ρ\rho is the Resistivity

LL the length



the radius is 

r=d2r=0.30mm2r=0.15mmr=\dfrac{d}{2} \\ r=\dfrac{0.30mm}{2}\\ r=0.15mm

Converting from millimeters to meters

r=0.15mm×1m1000mm=0.00015mr=0.15mm\times\dfrac{1m}{1000mm}=0.00015m


The wire area is

A=πr2A=\pi r^{2}

Evaluatin numerically

A=π(0.00015m)2A=\pi (0.00015m)^{2}

A=7.07×108m2A=7.07\times10^{-8}m^{2}

Getting the expression for the resistivity

R=ρLAR=\rho \dfrac{L}{A}

ALR=ρ\dfrac{A}{L}R=\rho


ρ=ALR\rho=\dfrac{A}{L}R

Evaluating numerically

ρ=7.07×108m22.25m×28Ω\rho=\dfrac{7.07\times10^{-8}m^{2}}{2.25m}\times 28 \Omega



The resistivity is

ρ=8.80×107Ωm\rho=8.80\times10^{-7}\Omega m



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