Answer to Question #302558 in Electric Circuits for Lia

Question #302558

1. Calculate the drift velocity of the electrons in a 12-gauge copper wire which has a diameter of 2. 5 mm carrying    an 18.0 A , given that there is one free electron per copper atom. The density of copper is 8.80x10kg/m3.

    atomic mass of copper = 63.54 g/mol; Avogadros number = 6.02 x 10 23 atoms/mol


2. Calculate the total DC resistance of a 100 meter roll of 2.0mmcopper wire if the resistivity of copper at 200  C is 1.72 x 10-8 ohm meter.


1
Expert's answer
2022-02-28T10:40:55-0500

Explanations &Calculations


1.

A.M.UCu=0.06354kgmol1L=6.02×1023atomsmol1L/A.M.U=92.7×1023atoms/kg1#ofen=92.7×1023atomskg1×8.80×103kgm3×1enatom1=8.16×1028enm3I=v.A.n.e18.0Cs1=v.[π.0.25.(2.5×103m)2].(8.16×1028enm3).(1.6×1019Cen1)\qquad\qquad \begin{aligned} \small A.M.U_{Cu}&=\small 0.06354\,kg\,mol^{-1}\\ \small L&=\small 6.02\times10^{23}\,atoms\,mol^{-1}\\ \small L/A.M.U&=\small 92.7\times10^{23}\,atoms/kg^{-1}\\ \\ \small \# of \,en&=\small 92.7\times10^{23}\,atoms\,kg^{-1}\times8.80\times10^3\,kgm^{-3}\times1\,en\,atom^{-1}\\ &=\small 8.16\times10^{28}\,en\,m^{-3}\\ \\ \small I&=\small v.A.n.e\\ \small 18.0\,Cs^{-1}&=\small v.[\pi.0.25.(2.5\times10^{-3}\,m)^2]. (8.16\times10^{28}\,en\,m^{-3}).(1.6\times10^{-19}C\,en^{-1}) \end{aligned}

  • Now you can simplify and get the answer.


2.

  • Just use the formula for resistance which is R=ρLArea\small R= \large\rho\frac{L}{Area}
  • Input all the given values in their SI forms and get the answer for resistance; so the square millimetre needs to be in square metres.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment