When a 12.0 car battery power a single 30.0w headlight how many electrons pass through it each second
P=VI30=12II=2.5ABut Q=ItQ=2.5CP=VI\\30=12I\\I=2.5A\\But\ Q=It\\Q=2.5C\\P=VI30=12II=2.5ABut Q=ItQ=2.5C
Charge on one electron=1.6×10−19C=1.6×10^{-19}C\\=1.6×10−19C
Number of electrons
=2.51.6×10−191.5625×1019electrons=\frac{2.5}{1.6×10{-19}}\\ 1.5625×10^{19} electrons=1.6×10−192.51.5625×1019electrons
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