Question #30204

A platinum resistance thermometer has resistance of 52.5 ohms and 9.75 ohms at 0 degrees celcius and 100 degrees celcius respectively.when the resistance is 8.25 ohms,find the temperature.

Expert's answer

Question 30599

The dependence of resistance on temperature is linear. Hence, in general it might be expressed as R=R0(1+αt)R = R_{0}(1 + \alpha t) .

Using condition that R=52.5Ω,t=0CR = 52.5\Omega, t = 0C obtain R0=52.5ΩR_0 = 52.5\Omega

Using the condition that R=9.75,t=100CR = 9.75, t = 100C obtain α=(9.75/52.5)1100=0.0811C\alpha = \frac{(9.75 / 52.5) - 1}{100} = -0.081\frac{1}{C} .

Hence, for current case, R=52.5(10.0081t)R = 52.5(1 - 0.0081t) .

Plugging R=8.25ΩR = 8.25\Omega into latter formula and solving for t obtain t=(1(8.2552.5))0.0081=104.06Ct = \frac{(1 - (\frac{8.25}{52.5}))}{0.0081} = 104.06C .

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