At what distance from this particle does its field have a magnitude of 12.0 N/C
Solution
Let consider we have a particle of charge Q
Then electric field at distance r
r=kQE=9∗109Q12=2.74Qr=\sqrt{\frac{kQ}{E}}\\=\sqrt{\frac{9*10^9Q}{12}}\\=2.74\sqrt{Q}r=EkQ=129∗109Q=2.74Q m so put Q value we get desired solution.
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