Question

Calculate the capacitance of a capacitor with separation distance of 800m with an area 1.25kmsquare.The permittivity of free space is 8.892*10^-13

Answer 1

C$=\frac{\epsilon0A}{d}$

$C=\frac{8.892×10^{-13}×1.25×10^6}{800}$

$=1.389nF$