Answer to Question #299344 in Electric Circuits for hsaushauhaus

Question

two charges one of magnitude 3 micro coulomb and the other of magnitude 5 micro coulomb if the force between them is 20 n ?

negative charge of -200 micro coulomb and a positive charge of 800 micro coulomb are separated by a distance of 30 centimeters. What is the force between the two charges?

Answer 1

a)

$F=\frac{Kq_1q_2}{r^2}$

$20=\frac{9×10^9×5×3×10^{-12}}{r^2}$

$r=8.216cm$

b)

$\begin{vmatrix} F \end{vmatrix}=\frac{9×10^9×200×800×10^{-12}}{(30×10^{-2})^2}$

$=1.6×10^4N$