Two charges q and Q are separated by a distance R. If both charges are doubled to 2q and 2Q but the distance R remains the same, the new electric force is _____ the old force.
Explanations & Calculations
F=kQ.qR2⋯ ⋯(1)F1=k(2Q).(2q)R2=4[kQ.qR2]=4.F\qquad\qquad \begin{aligned} \small F&=\small k\frac{Q.q}{R^2}\qquad\cdots\,\cdots(1)\\ \\ \small F_1&=\small k\frac{(2Q).(2q)}{R^2}\\ &=\small 4\Big[k\frac{Q.q}{R^2}\Big]\\ &=\small 4.F \end{aligned}FF1=kR2Q.q⋯⋯(1)=kR2(2Q).(2q)=4[kR2Q.q]=4.F
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