Question #297855

How much ice at -20°c must be dropped on 0.5 kilograms of water initially at 20°c in oder for the final temperature to be 0°c with the ice all melted. Heat capacity of container can be neglected

1
Expert's answer
2022-02-15T11:01:44-0500

Specific heat capacity of water C=4184J/kgC=4184J/kg /K/K

Specific heat capacity of Ice =2093Jkg1K1=2093Jkg^{-1}K^{-1}


Lf=334000J/kgL_f=334000J/kg


Heat lost by water =mcΔθ=mc\Delta\>\theta

=0.5×4184×20=0.5×4184×20

=41840J=41840J

Heat gained by ice=m(2093)(20)+m(334000)=m(2093)(20)+m(334000)

=375860m=375860m


375860m=41840375860m=41840

m=0.1113kgm=0.1113kg





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