Question #297426

A triode passes a plate current of 5mA at plate voltage 150V and grid voltage of -2V. If the grid voltage is changed to -35V, the plate current drops to 3.2mA but can be restored to 5mA by increasing plate voltage to 195V. Calculate


(1) mutual conductance


(2) a.c. plate resistance


(3) amplification factor


1
Expert's answer
2022-02-14T14:28:00-0500

1) mutual conductance

gm=changeinanodecurrentchangeingridvoltageg_m= \frac{change\> in \>anode\> current}{change\>in\> grid\> voltage}


=(3.25)×10335(2)=5.4645×105mho=\frac{(3.2-5)×10^{-3}}{-35-(-2)}=5.4645×10^{-5}mho


2) ac plate resistance

rp=smallincrementinanodevoltageSmallchangeinanodecurrentr_p=\frac{small\> increment\> in \>anode\> voltage}{Small\> change\, in\> anode\> current}


=195150(53.2)×103=2.5×104Ω=\frac{195-150}{(5-3.2)×10^{-3}}=2.5×10^4\Omega



3) Amplification factor


μ=changeinanodevoltagechangeingridvoltage\mu=\frac{change\> in\> anode \>voltage}{change\> in \>grid \>voltage}


=19515035(2)=1.3636=\frac{195-150}{-35-(-2)}=-1.3636


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS