Calculate the capacitance of two plates area 4cm² seperated by 1mm
C=ϵ0Ad=\frac{\epsilon_0A}{d}=dϵ0A
C =8.85×10−12×4×10−41×10−3=\frac{8.85×10^{-12}×4×10^{-4}}{1×10^{-3}}=1×10−38.85×10−12×4×10−4
=3.54×10−12=3.54×10^{-12}=3.54×10−12 F
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