Question #295993

Suppose you need a capacitor bank with a total capacitance of 0.750-mF but you have only 1.50-mF capacitors at your disposal. What is the smallest number of capacitors you could connect together to achieve your goal, and how would you connect them?

1
Expert's answer
2022-02-10T13:38:01-0500

Explanation & Answer


  • The required capacitance is half of the capacitance of a single capacitor.
  • So, simply you can connect a minimum of 2 capacitors in series to get the capacitance halved.
  • This is because when capacitors are connected in series, the net capacitance is reduced.

1Cnet=11.50+11.50Cnet=1.502=0.750mF\qquad\qquad \begin{aligned} \small \frac{1}{C_{net}}&=\small \frac{1}{1.50}+\frac{1}{1.50}\\ \small C_{net} &=\small \frac{1.50}{2}\\ &=\small 0.750\,mF \end{aligned}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS