a cell has an e.m.f. of 3v. when it is connected across a resistor of resistance 4ohms, a current of 0.5a passes through the current. calculator the internal resistance
Gives E=3VR=4Ωi=0.5AE=3V\\R=4\Omega\\i=0.5AE=3VR=4Ωi=0.5A
We know that
I=ER+rI=\frac{E}{R+r}I=R+rE
0.5=34+r0.5=\frac{3}{4+r}0.5=4+r3
2+0.5r=32+0.5r=32+0.5r=3
r=105=2Ωr=\frac{10}{5}=2\Omegar=510=2Ω
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