What current must flow if 0.24 coulombs is to be transferred in 15ms? *
1ms=0.001sec1ms=0.001sec1ms=0.001sec
15ms=0.015sec15ms=0.015sec15ms=0.015sec
III=QT=\frac{Q}{T}=TQ
I=0.240.015I=\frac{0.24}{0.015}I=0.0150.24
I=16AmpereI=16 AmpereI=16Ampere
Hence, 16 Ampere will flow in the current
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