Inductor as a component in transformer used 10 k resistor. Calculate the maximum
voltage that can be applied to achieve a power of 0.15W
Answer
power of P=0.15W
Resistor R =10KΩ\OmegaΩ
Maximum voltage is given by
V=PR=0.15×10000=38.73VV=\sqrt{PR}\\=\sqrt{0.15\times10000}\\= 38.73VV=PR=0.15×10000=38.73V
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