Determine the net capacitance C of each network of capacitors shown below. Assume that =1.0pF, =2.0pF,=4.0pF and =5.0pF. Find the charge on each capacitor, assuming there is a potential difference of 12.0V across each network.
Answer
All charges in parallel so
Equivalent capacitance is
Given by
"C_e=C_1+C_2+C_3+C_4\\\\=1+2+4+5\\\\=12pF"
V=12V
Charge on each capacitor
"Q_1=C_1V=1pF\\times12=12pC\\\\Q_2=C_2V=2pF\\times12=24pC\\\\Q_3=C_3V=4pF\\times12=48pC\\\\Q_4=C_4 V=5pF\\times12=60pC"
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