Question

A set of parallel plates has a capacitance of 5.0µF. How much charge must be added to the plates to increase the potential difference between them by 100 V?

Answer 1

We know that

Charge

$Q=CV$

$Q=500\mu F$

$$Q=5\times10^{-6}\times100=500\times10^{-6}$$

$Q=500\mu C$

Charge of capacitor C=500$\mu C$