A certain class of lamp takes 0.45A at 220V. How many such lamps can be run for an expenditure of power equal to 1 1/3 horsepower?
Power
P=IV
Now power
P=0.45×220=99WP=0.45\times220=99WP=0.45×220=99W
P′=113P'=\frac{11}{3}P′=311 Hp
P′=11×7463=2735.33WP'=\frac{11\times746}{3}=2735.33WP′=311×746=2735.33W
Number of lamp=P′P\frac{P'}{P}PP′
n=2735.3399=27.62n=\frac{2735.33}{99}=27.62n=992735.33=27.62
n=27n=27n=27 (Approximately)
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