Question #293073

A certain class of lamp takes 0.45A at 220V. How many such lamps can be run for an expenditure of power equal to 1 1/3 horsepower?

Expert's answer

Power

P=IV

Now power

P=0.45×220=99WP=0.45\times220=99W

P=113P'=\frac{11}{3} Hp

P=11×7463=2735.33WP'=\frac{11\times746}{3}=2735.33W

Number of lamp=PP\frac{P'}{P}

n=2735.3399=27.62n=\frac{2735.33}{99}=27.62

n=27n=27 (Approximately)


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