Two capacitor of capacitance C1 and C2 connected in series are joined to two other capacitors of capacitance of capacitances C3 and C4, which are connected in parallel .determine the equivalent capacitance of the circuit .
The two capacitors conected in series
"C_s=\\frac{C_1C_2}{C_1+C_2}"
Two capacitors connected in parallel
"C_p= C_3+C_4"
"C_{total}=\\frac{C_1+C_2}{C_1C_2}+\\frac{1}{C_3+C_4}\\\\=\\frac{C_1C_2+C_1C_3+C_1C_4+C_2C_3+C_2C_4}{(C_1C_2)(C_3+C_4)}"
Comments
Leave a comment