Question #291628

A 0.40 mm diameter copper wire carries a current of

3μA. Find the current density and he electron drift density in the wire


1
Expert's answer
2022-01-31T10:43:13-0500

Now current density

J=IAJ=Iπr2J=\frac{I}{A}\\J=\frac{I}{\pi r^2}

r=D2=0.2mmr=\frac{D}{2}=0.2mm


A=πr2=3.14×(0.2×103)2=3.14×4×108A=\pi r^2=3.14\times(0.2\times10^{-3})^2=3.14\times4\times10^{-8}

J=3×1063.14×4×108=23.88A/m2J=\frac{3\times10^{-6}}{3.14\times4\times10^{-8}}=23.88A/m^2

Drift velocity

Vd=JneV_d=\frac{J}{ne}


Vd=23.888.49×1028×1.6×1019=4.5×109m/secV_d=\frac{23.88}{8.49\times10^{28}\times1.6\times10^{-19}}=4.5\times10^{-9}m/sec


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