A certain class of lamp takes 0.45A at 220V. How many such lamp can be run for an expenditure of power equal to 1 1/3 horsepower?
Answer
Current in lamp I=0.45A
Voltage V=220V.
Power of single lamp
P=VI=220×0.45=99Watts.220\times0.45=99 Watts.220×0.45=99Watts.
Now given power
No of Bulb.=113×74699=852No \space of \space Bulb. =\frac{113\times746}{99}=852No of Bulb.=99113×746=852
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