a sheet of polythene(er=1.3) and 0.5mm thickis to be used in capacitor by sandwiching it two sheet of aluminum foil.what area must sheets have
Solution
C=ϵrϵ0AdC=\frac{\epsilon_r\epsilon_0A}{d}C=dϵrϵ0A
∴ A=5×10−6×0.5×10−38.85×10−12×1.3\therefore\>A=\frac{5×10^{-6}×0.5×10^{-3}}{8.85×10^{-12}×1.3}∴A=8.85×10−12×1.35×10−6×0.5×10−3
=217.3m2=217.3m^2=217.3m2
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