Question #290997

a sheet of polythene(er=1.3) and 0.5mm thickis to be used in capacitor by sandwiching it two sheet of aluminum foil.what area must sheets have

1
Expert's answer
2022-01-28T12:48:07-0500



Solution


C=ϵrϵ0AdC=\frac{\epsilon_r\epsilon_0A}{d}


A=5×106×0.5×1038.85×1012×1.3\therefore\>A=\frac{5×10^{-6}×0.5×10^{-3}}{8.85×10^{-12}×1.3}


=217.3m2=217.3m^2



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