At what distance a long, straight wire carrying a current of 3 A can develop a
        magnetic field of 7x10-7 T
Answer
Let this distance is d.
Current through wire I=3A
Magnetic field B="7\\times10^{-7}T"
Then distance is given by
"d=\\frac{\\mu_0 2 I}{4\\pi B}"
Putting all values
"d=\\frac{10^{-7}\\times 3\\times2}{7\\times10^{-7}}\\\\=0.86m"
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