Answer to Question #289837 in Electric Circuits for boshra

Question #289837

 Find the current in a long, straight wire needed to develop a magnetic field of    

       5x10-7 T at 6m from the wire.


1
Expert's answer
2022-01-25T07:11:12-0500

We shall find the current which is needed to develop the magnetic field of 55 X 107T10^{-7}T


From the question, we have the parameters

B=5B=5 X 107T10^{-7}T

length, x=6mx=6m

Current, I=?I=?


Now,

Using the formula

B=μoI2πx\displaystyle B=\frac{\mu_{o} I}{2\pi x}


We shall make II the subject of the equation

We have


I=2πxBμo\displaystyle I=\frac{2\pi x B}{\mu_{o}}


where μo=4π×107\mu_{o}=4\pi \times 10^{-7}


Substituting into the formula, we have

I=2π×6×5×1074π×107\displaystyle I=\frac{2\pi \times 6\times 5\times10^{-7}}{4\pi \times 10^{-7}}


I=1×30×1072×107\displaystyle I=\frac{1 \times 30\times10^{-7}}{2 \times 10^{-7}}


I=30×1072×107\displaystyle I=\frac{30\times10^{-7}}{2 \times 10^{-7}}


I=302\displaystyle I=\frac{30}{2}


I=15AI=15A

which is the needed current to develop the magnetic field of 5×107T5\times10^{-7}T



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