Answer to Question #289809 in Electric Circuits for AA7

Question

The voltage across a 10 μF capacitor to charge it with 10 mC is

Answer 1

C = 10 uF = $10 * 10^{-6} F$

Q = 10 mC = $10 * 10^{-3} C$

Q = C V

Therefore

V = $\frac{Q}{C}$ = $\frac{10*10^{-3}}{10*10^{-6}}$ = 1000V

V = 1000 V