Answer to Question #289809 in Electric Circuits for AA7

Electric Circuits

Question #289809

The voltage across a 10 μF capacitor to charge it with 10 mC is

Expert's answer

C = 10 uF = "10 * 10^{-6} F"

Q = 10 mC = "10 * 10^{-3} C"

Q = C V

Therefore

V = "\\frac{Q}{C}" = "\\frac{10*10^{-3}}{10*10^{-6}}" = 1000V

V = 1000 V

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