Question #288310

Determine (a) the peak frequency deviation, (b) minimum bandwidth, and (c) baud for a binary FSK signal with a mark frequency of 38 kHz, a space frequency of 40 kHz, and an input bit rate of 4 kbps.


Expert's answer

a)

2Δ f=∣fm−fs∣2\Delta\>f=|fm-f_s|

Δ f=(40−38)2=1kHz\Delta\>f=\frac{(40-38)}{2}=1kHz


b)

Bmin=2(Δ f+fb)B_{min}=2(\Delta\>f+f_b)

=2(1+4)=2(1+4)

=10kHz=10kHz


c)

Baud for a binary FSK =fbN=\frac{f_b}{N} where N=1N=1


=40001=4000=\frac{4000}{1}=4000


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