Answer to Question #287816 in Electric Circuits for Farishaaa

Question

Two charges q1 = -6 µC and q2 = +10 µC are placed 12 cm apart. Another charge, q=-2 μC is placed in the middle. Determine the magnitude and direction of the force acting on q3 by the charge q1 and 92.

Answer 1

$|F_{13}|$on $q_3$ due to $q_1$ is repulsive directed towards right.

$|F_{23}|$ on $q_3$ due to $q_2$ is attractive directed toward right

$|F_{q3}|=|F_{13}|+|F_{23}|$

$=8.99×10^9×2×10^{-6}(\frac{6×10^{-6}}{0.06^2} +\frac{10×10^{-6}}{0.06^2})$

$=79.91N$

$F_{q3}$ is directed toward right