Question #28438

The heater wire in a small stoVe is made of iron ribbon wire 0.1 cm by 0.5 cm in rectangular cross-section and 2 m long. calculate its resistance

Expert's answer

The heater wire in a small stove is made of iron ribbon wire 0.1 cm by 0.5 cm in rectangular cross-section and 2 m long. Calculate its resistance.

**Solution.**

The resistance is determined by the following formula:


R=ρIS,R = \frac {\rho I}{S},


where ρ=9.71106ohmm\rho = 9.71 \cdot 10^{6} \mathrm{ohm} \cdot \mathrm{m} is the resistivity of iron, I=2 mI = 2 \mathrm{~m} is the length of the wire, SS is the cross-section area. Find SS knowing that the cross-section is rectangular:


S=0.10.5=0.05cm2=5106m2.S = 0.1 \cdot 0.5 = 0.05 \mathrm{cm}^2 = 5 \cdot 10^{-6} \mathrm{m}^2.


So we can find the resistance as follows:


R=9.7110825106=0.039ohm.R = \frac {9.71 \cdot 10^{-8} \cdot 2}{5 \cdot 10^{-6}} = 0.039 \mathrm{ohm}.


Answer: 0.039 ohm.

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