If a clock expends 2 W of power from a 1.5 V battery, what amount of current is supplying the clock? Ans: 1.3 A
Gives
P=2W
V=1.5 V
We know that
P=IVI=PVP=IV \\I=\frac{P}{V}P=IVI=VP
Put value
I=21.5=1.3AmpI=\frac{2}{1.5}=1.3AmpI=1.52=1.3Amp
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