A resistor of resistance 12 Ω has a current of 2.0 a flowing through it. How much energy is generated in the resistor in 1 minute?
Solution;
Given;
Resistance,R=12Ω12\Omega12Ω
Current,I=2A2A2A
Time,t=1m=60s1m=60s1m=60s
Hence;
Power in the resistor is;
P=I2RP=I^2RP=I2R
P=22×12=48WP=2^2×12=48WP=22×12=48W
Energy generated is;
E=PtE=PtE=Pt
E=48×60=2880JE=48×60=2880JE=48×60=2880J
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