The resistance in a fixed length of a wire of circular cross-section is 10.0 Ω. What will be the resistance of a wire of the same length made with the same material but with only half radius? Ans: 40 Ω
R1=ρl/A1=ρl/(πr2)R_1=\rho l/A_1=\rho l/(\pi r^2)R1=ρl/A1=ρl/(πr2)
R2=ρl/A2=ρl/(π(r/2)2)=4ρl/(πr2)=4R1=4⋅10=40 (Ω)R_2=\rho l/A_2=\rho l/(\pi (r/2)^2)=4\rho l/(\pi r^2)=4R_1=4\cdot10=40\ (\Omega)R2=ρl/A2=ρl/(π(r/2)2)=4ρl/(πr2)=4R1=4⋅10=40 (Ω)
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