Question

0.800 watts of power are dissipated in a cell of emf 10.0 volts. If the internal resistance is 2.40 ȍ, find the resistance of the load and the current in the load. 

Answer 1

$P=I^2R$

$0.8=I^2×2.4$

$I=0.57735$

Lost voltage $=0.57735×2.4$

$=1.38564V$

Terminal voltage $=10-1.38564$

$=8.61436$

Resistance of load $=\frac{8.61436}{0.57735}$

$=14.92052\Omega$

$\therefore$ current in load and resistance of load

$=0.57735A$

and $14.92052\Omega$