A 12 ȍ resistor has a potential difference of 4.0 volts. Determine the power dissipated in the resistor.
power dissipated in the resistor:
P=UI=U2/R=42/12=1.33P=UI=U^2/R=4^2/12=1.33P=UI=U2/R=42/12=1.33 W
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