Question #280993

A 12 ȍ resistor has a potential difference of 4.0 volts. Determine the power dissipated in the resistor. 


1
Expert's answer
2021-12-24T11:32:48-0500

power dissipated in the resistor:


P=UI=U2/R=42/12=1.33P=UI=U^2/R=4^2/12=1.33 W


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