Answer to Question #280992 in Electric Circuits for Anonymous005

Question #280992

A 12 volt supply is in series with a resistor and an LDR. In light, the LDR has a potential difference of 3.0 volts and in the dark it has a potential difference of 6.0 volts. Find the ratio of the series resistor to the resistance of the LDR in light.  


1
Expert's answer
2021-12-24T11:34:06-0500

Assuming there is no other resistance in the circuit


Sum of p.d. across LDR and resistor is12V12V


VRV\propto\>R


Where V=V= voltage

R=ResistanceR=Resistance


In light p.d across LDR=3V=3V

p.d\therefore\>p.d across R =123=12-3 =9V=9V


Ratio of voltage =9:3=9:3

=3:1=3:1


    \implies Ratio of resistance =3:1=3:1


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