Question #279948

A plane flies from base camp to lake A, a distance of 280 km at a direction of 20 degrees north of east. After dropping off supplies, the plane flies to lake B, which is 190km and 30 degree west of north from lake A.





Expert's answer







Analyzing the diagram

Let x=x= the distance between Base Camp and Lake B


Angle β°=180(70+30)\beta°=180-(70+30)

=80°=80°


Using cosine rule

x2=1902+28022×190×180Cos80x^2=190^2+280^2-2×190×180\>Cos\>80

x=309.88kmx=309.88km



Using Sine Rule

309.88Sin80=280Sin(θ+30)\frac{309.88}{Sin80}=\frac{280}{Sin({\theta}+30)}


Sin (θ+30)=0.8898(\theta+30)=0.8898

θ=32.85\theta=32.85


To return to Base the plan flies 309.88km309.88km at a direction of 32.85°32.85° west of south from Lake B


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