A plane flies from base camp to lake A, a distance of 280 km at a direction of 20 degrees north of east. After dropping off supplies, the plane flies to lake B, which is 190km and 30 degree west of north from lake A.
Analyzing the diagram
Let "x=" the distance between Base Camp and Lake B
Angle "\\beta\u00b0=180-(70+30)"
"=80\u00b0"
Using cosine rule
"x^2=190^2+280^2-2\u00d7190\u00d7180\\>Cos\\>80"
"x=309.88km"
Using Sine Rule
"\\frac{309.88}{Sin80}=\\frac{280}{Sin({\\theta}+30)}"
Sin "(\\theta+30)=0.8898"
"\\theta=32.85"
To return to Base the plan flies "309.88km" at a direction of "32.85\u00b0" west of south from Lake B
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