Question #279425

The rubber cord of a catapult has a cross sectional area 1.0mm^2 and a total unstretched length 10.0cm. It I stretched to 12.0cm and then released to project a missile of mass 5.0g. From energy considerations, or otherwise, calculate the velocity of projection, taking the young modulus for the rubber as 5.0x10^8 Pa. State the assumptions made in your calcukation

1
Expert's answer
2021-12-14T15:09:04-0500

Potentional energy of the stretched cord

Ep=E×S×δl22lE_p=\frac{E\times S\times\delta l^2}{2l}

where E - young modulus, S - cross sectional area, l - unstretched length, δl\delta l - difference in length.

Ep=5×108×106×2×0.0222×0.1=2JE_p=\frac{5\times 10^8 \times 10^{-6} \times2\times 0.02^2}{2\times0.1}=2J

Kinetic energy of the missile:

Ek=mV22E_k=\frac{mV^2}{2}

Velocity:

V=2Ekm=2×25=0.9m/sV=\sqrt\frac{2E_k}{m}=\sqrt\frac{2\times2}{5}=0.9m/s

Assumption is cord's cross sectional area doesnt change during stretching.


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