Question

a three resistors of 4ohms, 12 ohms and 5 ohms are connected in parallel. if total current is 12A, find the current through each resistor

Answer 1

Total resistance $R_T=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

$\frac{1}{R_T}=\frac{1}{4}+\frac{1}{12}+\frac{1}{5}= \frac{8}{15}$

$R_T=1.87ohms$

V=IR

V= 12×1.87=22.5V

$I_1=\frac{22.5}{4}=5.625A$

$I_2=\frac{22.5}{12}=1.875A$

$I_3=\frac{22.5}{5}=4.5A$