Question #27917

A reflecting, spherical Christmas tree ornament has a diameter of 9.0 cm. A child looks at the ornament from a distance of 24 cm. Describe the image she sees.
Where is the image located?

Expert's answer

A reflecting, spherical Christmas tree ornament has a diameter of 9.0cm9.0\mathrm{cm} . A child looks at the ornament from a distance of 24cm24\mathrm{cm} . Describe the image she sees. Where is the image located?

Solution.


Spherical Christmas tree ornament is the convex mirror.

The symbols in the diagram:

dod_{o} - a distance from the object to the mirror;

did_{i} - a distance from the image to the mirror;

ff - a focal length of the mirror;

ABAB - object;

A1B1A_{1}B_{1} - image.

The mirror equation:


1do+1di=1f.\frac {1}{d _ {o}} + \frac {1}{d _ {i}} = \frac {1}{f}.

ff is negative, because the mirror is convex.

did_{i} is negative, because the image is formed behind the mirror.


1do1di=1f.\frac {1}{d _ {o}} - \frac {1}{d _ {i}} = - \frac {1}{f}.


A focal length of the mirror:


f=r2;f = \frac{r}{2};

rr - the radius of the spherical mirror.


r=d2;r = \frac{d}{2};f=d4.f = \frac{d}{4}.1do1di=4d.\frac{1}{d_o} - \frac{1}{d_i} = -\frac{4}{d}.1di=1do+4d;\frac{1}{d_i} = \frac{1}{d_o} + \frac{4}{d};1di=d+4doddo;\frac{1}{d_i} = \frac{d + 4 d_o}{d \cdot d_o};di=ddod+4do.d_i = \frac{d \cdot d_o}{d + 4 d_o}.di=0.090.240.09+40.24=0.02(m)=2(cm).d_i = \frac{0.09 \cdot 0.24}{0.09 + 4 \cdot 0.24} = 0.02(m) = 2(cm).


Answer: A child sees the virtual upright diminished image of himself. The image is located behind the mirror. The distance from the image to the mirror is: di=2cmd_i = 2\mathrm{cm}.


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